Topic 8 / 17intermediate
Functions of Several Variables
Determine domains, sketch surfaces $z = f(x,y)$, and visualize them with traces, level curves, and contour maps.
A function assigns a real number to each pair in its domain. The graph is a surface in 3D. We understand surfaces by **traces** (slices at fixed values) and **contour maps** (level curves).
Domain of $f(x, y)$
Find restrictions: denominators , square root expressions , log arguments , etc. Express as a region in the -plane.
Surfaces and traces
Set one variable to a constant and sketch the resulting cross-section in the other two:
- trace: solve — produces a **level curve** (contour).
- trace: substitute and solve in the -plane.
- trace: substitute and solve in the -plane.
Combining these traces builds intuition for the full surface.
Level curves and contour maps
The level curve is the set of where takes value . A contour map plots several level curves at evenly spaced -values; **closely spaced contours indicate steep terrain**, widely spaced contours indicate flat terrain.
Strategy tips
- Use level curves to spot circular symmetry: has concentric circles.
- Saddle points show as crossed contours.
Level surfaces (3 variables)
For , the **level surface** is a 2D surface in 3D. Common examples: (sphere shells), (paraboloid shells).
Recognizing common surfaces
Quick visual cues:
- → plane.
- → upward paraboloid (level curves are circles).
- → saddle (hyperbolic level curves).
- → upper half cone.
Worked examples
Example 1
Find the domain of .
- 1Log argument positive: (open disk of radius 2).
- 2Square root nonnegative: .
- 3Intersect.
Answer
Strip inside the open disk of radius 2.Example 2
Sketch level curves of for .
- 1: — two lines.
- 2: — hyperbola with branches opening left/right.
- 3: — hyperbola with branches opening up/down.
- 4Together: a saddle pattern with crossed asymptotes through the origin.
Answer
Hyperbolas; sign of flips orientation. Asymptote lines pass through saddle.Example 3
Match the function to its graph: (i) , (ii) .
- 1(i) Concentric ripples — sine of distance from origin, periodic.
- 2(ii) Bell-shaped peak at origin, decays to 0 outward.
Answer
(i) ripple pattern; (ii) Gaussian bell.Interactive visualizations
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Saddle: . Note how it goes up along and down along .
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Contour map of . Concentric circles; closer rings indicate steeper slope.
Formulas in this topic
Level curve
Set of points where f equals c.
Level surface
Set in 3D where 3-variable f equals c.
Circular paraboloid
Upward; level curves are circles.
Saddle
Hyperbolic level curves.
Cone (upper half)
Apex at origin, opens upward.